For some θ∈(0,2π), let the eccentricity and the length of the latus rectum of the hyperbola x2−y2sec2θ=8 be e1 and l1, respectively, and let the eccentricity and the length of the latus rectum of the ellipse x2sec2θ+y2=6 be e2 and l2, respectively. If e12=e22(sec2θ+1), then (e1e2l1l2)tan2θ is equal to ____
Held on 28 Jan 2026 · Verified 6 Jul 2026.
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