y2=4(x+4) Equation of circle (x+3)2+y2=25 Passes through the point of intersection of two lines 3x−y=0 and x+λy=4 (3λ+14,3λ+112), we get $\begin{aligned}
& \lambda=-\frac{7}{6}, 1 \
& 12 \lambda_1+29 \lambda_2 \
& -14+29=15
\end{aligned}$
The focus of the parabola y^2=4 x+16 is the centre of the circle C of radius 5 . If the values of λ, for which C passes through the point of…
JEE Main 2025 — Mathematics Coordinate Geometry
The focus of the parabola y2=4x+16 is the centre of the circle C of radius 5 . If the values of λ, for which C passes through the point of intersection of the lines 3x−y=0 and x+λy=4, are λ1 and λ2,λ1<λ2, then 12λ1+29λ2 is equal to
Held on 23 Jan 2025 · Verified 6 Jul 2026.
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Coordinate Geometry in other years
More JEE Main Coordinate Geometry questions
Let $A,B$ be points on the two half-lines $x-\sqrt{3}|y|=\alpha$, $\alpha>0$ at a distance of $\alpha$ from their point of intersection $P$. The line segment $AB$ meets the angle bisector of the given half-lines at the point $Q$. If $PQ=\dfrac{9}{2}$ and $R$ is the radius of the circumcircle of $\triangle PAB$, then $\dfrac{\alpha^2}{R}$ is equal to ______
If a straight line drawn through the point of intersection of the lines $4x+3y-1=0$ and $3x+4y-1=0$, meets the co-ordinate axes at the points P and Q, then the locus of the mid point of PQ is:
Let $C$ be a circle having centre in the first quadrant and touching the $x$-axis at a distance of $3$ units from the origin. If the circle $C$ has an intercept of length $6\sqrt{3}$ on $y$-axis, then the length of the chord of the circle $C$ on the line $x - y = 3$ is :
Let O be the origin, and P and Q be two points on the rectangular hyperbola $xy = 12$ such that the mid point of the line segment PQ is $\left(\dfrac{1}{2}, -\dfrac{1}{2}\right)$. Then the area of the triangle OPQ equals:
Let the vertex $A$ of a triangle $ABC$ be $(1, 2)$, and the mid-point of the side $AB$ be $(5, -1)$. If the centroid of this triangle is $(3, 4)$ and its circumcenter is $(\alpha, \beta)$, then $21(\alpha + \beta)$ is equal to:
Other Mathematics topics for JEE Main
Keep practicing Coordinate Geometry
Work through every JEE Main Coordinate Geometry PYQ, year by year.