$\begin{gathered}
7 x+4 y=15 \
7 x+7 y+10=0
\end{gathered}$
distance between P and B=5
Let the three sides of a triangle are on the lines 4x−7y+10=0,x+y=5 and 7x+4y=15. Then the distance of its orthocentre from the orthocentre of the triangle formed by the lines x=0,y=0 and x+y=1 is
Held on 4 Apr 2025 · Verified 6 Jul 2026.
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