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Let the equation of the circle, which touches x-axis at the point (a, 0), agt0 and cuts off an intercept of length b on y-axis be x^2+y^2-α x+β…

JEE Main 2025 — Mathematics Coordinate Geometry

2025mcqmedium

Let the equation of the circle, which touches xxx-axis at the point (a,0),a>0(a, 0), a\gt0(a,0),a>0 and cuts off an intercept of length bbb on yyy-axis be x2+y2−αx+βy+γ=0x^2+y^2-\alpha x+\beta y+\gamma=0x2+y2−αx+βy+γ=0. If the circle lies below xxx-axis, then the ordered pair (2a,b2)\left(2 a, b^2\right)(2a,b2) is equal to

Official previous-year question

Held on 28 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    (γ,β2−4α)\left(\gamma, \beta^2-4 \alpha\right)(γ,β2−4α)

  2. B

    (α,β2+4γ)\left(\alpha, \beta^2+4 \gamma\right)(α,β2+4γ)

  3. C

    (γ,β2+4α)\left(\gamma, \beta^2+4 \alpha\right)(γ,β2+4α)

  4. D

    (α,β2−4γ)\left(\alpha, \beta^2-4 \gamma\right)(α,β2−4γ)

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