Let the equation of the circle, which touches x-axis at the point (a,0),a>0 and cuts off an intercept of length b on y-axis be x2+y2−αx+βy+γ=0. If the circle lies below x-axis, then the ordered pair (2a,b2) is equal to
Held on 28 Jan 2025 · Verified 6 Jul 2026.
(γ,β2−4α)
(α,β2+4γ)
(γ,β2+4α)
(α,β2−4γ)
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Let the image of parabola $x^{2}=4 y$, in the line $x-y=1$ be $(y+a)^{2}=b(x-c)$, $a, b, c \in \mathrm{~N}$. Then $a+b+c$ is equal to
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