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Let one focus of the hyperbola H: x^2 a^2- y^2 ~b^2=1 be at (√10, 0) and the corresponding directrix be x= 9 √10. If e and l respectively are the…

JEE Main 2025 — Mathematics Coordinate Geometry

2025mcqmedium

Let one focus of the hyperbola H:x2a2−y2 b2=1\mathrm{H}: \frac{\mathrm{x}^2}{\mathrm{a}^2}-\frac{\mathrm{y}^2}{\mathrm{~b}^2}=1H:a2x2​− b2y2​=1 be at (10,0)(\sqrt{10}, 0)(10​,0) and the corresponding directrix be x=910\mathrm{x}=\frac{9}{\sqrt{10}}x=10​9​. If e and lll respectively are the eccentricity and the length of the latus rectum of H , then 9(e2+l)9\left(\mathrm{e}^2+l\right)9(e2+l) is equal to:

Official previous-year question

Held on 2 Apr 2025 · Verified 6 Jul 2026.

Options

  1. A

    14

  2. B

    15

  3. C

    16

  4. D

    12

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