ae=10 and ea=109⇒a2=9 and e=310 Now ⇒(ae)2=a2+b210=9+b2⇒ b2=1ℓ=a2 b2=32(1)9(e2+ℓ)=9(910+32)=10+6=16
Let one focus of the hyperbola H:a2x2− b2y2=1 be at (10,0) and the corresponding directrix be x=109. If e and l respectively are the eccentricity and the length of the latus rectum of H , then 9(e2+l) is equal to:
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