Point of contact are (a2 m2+b2∓a2 m,a2 m2+b2±b2)
A(5−16,59)B(516,5−9)
Point D is (512,512)
Area of ABD=21−516516512595−9512111
=12
Area of ABCD is =24
option (2)
Let for two distinct values of p the lines y=x+p touch the ellipse E:42x2+32y2=1 at the points A and B . Let the line y=x intersect E at the points C and D. Then the area of the quadrilateral ABCD is equal to
Held on 4 Apr 2025 · Verified 6 Jul 2026.
36
24
48
20
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