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Let y^2=12 x be the parabola and S be its focus. Let PQ be a focal chord of the parabola such that ( SP)( SQ)= 147 4. Let C be the circle described…

JEE Main 2025 — Mathematics Coordinate Geometry

2025integerhard

Let y2=12xy^2=12 xy2=12x be the parabola and SSS be its focus. Let PQ be a focal chord of the parabola such that (SP)(SQ)=1474(\mathrm{SP})(\mathrm{SQ})=\frac{147}{4}(SP)(SQ)=4147​. Let C be the circle described taking PQ as a diameter. If the equation of a circle CCC is 64x2+64y2−αx−643y=β64 x^2+64 y^2-\alpha x-64 \sqrt{3} y=\beta64x2+64y2−αx−643​y=β, then β−α\beta-\alphaβ−α is equal to ________.

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Held on 29 Jan 2025 · Verified 6 Jul 2026.

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