a2x2−b2y2=1 a2b2=152 ...(i) 1+a2b2=25....(ii) From (i) and (ii) a=52 and b2=75 A2x2−B2y2=−1 B2A2=125 ....(iii) Since, product of transverse axis is =10010 (2A)⋅(2B)=10010 From (iii) and (iv) $\begin{aligned}
& A^2=150 \text { and } B=5 \sqrt{5} \
& e_2=\sqrt{1+\frac{A^2}{B^2}}=\sqrt{\frac{11}{5}} \
& \therefore 25 e_2^2=25\left(\frac{11}{5}\right)=55
\end{aligned}$