Skip to main content

Let H_1: x^2 a^2- y^2 ~b^2=1 and H_2:- x^2 ~A^2+ y^2 ~B^2=1 be two hyperbolas having length of latus rectums 15 √2 and 12 √5 respectively. Let their…

JEE Main 2025 — Mathematics Coordinate Geometry

2025integerhard

Let H1:x2a2−y2 b2=1\mathrm{H}_1: \frac{x^2}{\mathrm{a}^2}-\frac{y^2}{\mathrm{~b}^2}=1H1​:a2x2​− b2y2​=1 and H2:−x2 A2+y2 B2=1\mathrm{H}_2:-\frac{x^2}{\mathrm{~A}^2}+\frac{y^2}{\mathrm{~B}^2}=1H2​:− A2x2​+ B2y2​=1 be two hyperbolas having length of latus rectums 15215 \sqrt{2}152​ and 12512 \sqrt{5}125​ respectively. Let their ecentricities be e1=52e_1=\sqrt{\frac{5}{2}}e1​=25​​ and e2e_2e2​ respectively. If the product of the lengths of their transverse axes is 10010100 \sqrt{10}10010​, then 25e2225 \mathrm{e}_2^225e22​ is equal to ________.

Official previous-year question

Held on 24 Jan 2025 · Verified 6 Jul 2026.

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics