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Let e_1 and e_2 be the eccentricities of the ellipse x^2 ~b^2+ y^2 25=1 and the hyperbola x^2 16- y^2 ~b^2=1, respectively. If b lt 5 and e_1 e_2=1,…

JEE Main 2025 — Mathematics Coordinate Geometry

2025mcqmedium

Let e1e_1e1​ and e2e_2e2​ be the eccentricities of the ellipse x2 b2+y225=1\frac{\mathrm{x}^2}{\mathrm{~b}^2}+\frac{\mathrm{y}^2}{25}=1 \quad b2x2​+25y2​=1 and the hyperbola x216−y2 b2=1\quad \frac{\mathrm{x}^2}{16}-\frac{\mathrm{y}^2}{\mathrm{~b}^2}=116x2​− b2y2​=1, respectively. If b<5\mathrm{b} \lt 5b<5 and e1e2=1\mathrm{e}_1 \mathrm{e}_2=1e1​e2​=1, then the eccentricity of the ellipse having its axes along the coordinate axes and passing through all four foci (two of the ellipse and two of the hyperbola) is :

Official previous-year question

Held on 7 Apr 2025 · Verified 6 Jul 2026.

Options

  1. A

    45\frac{4}{5}54​

  2. B

    35\frac{3}{5}53​

  3. C

    74\frac{\sqrt{7}}{4}47​​

  4. D

    32\frac{\sqrt{3}}{2}23​​

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