Skip to main content

If the midpoint of a chord of the ellipse x^2 9+ y^2 4=1 is (√2, 4 / 3), and the length of the chord is 2 √α 3, then α is :

JEE Main 2025 — Mathematics Coordinate Geometry

2025mcqmedium

If the midpoint of a chord of the ellipse x29+y24=1\frac{x^2}{9}+\frac{y^2}{4}=19x2​+4y2​=1 is (2,4/3)(\sqrt{2}, 4 / 3)(2​,4/3), and the length of the chord is 2α3\frac{2 \sqrt{\alpha}}{3}32α​​, then α\alphaα is :

Official previous-year question

Held on 28 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    202020

  2. B

    222222

  3. C

    181818

  4. D

    262626

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics