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Let the foci of a hyperbola H coincide with the foci of the ellipse E: (x-1)^2 100+ (y-1)^2 75=1 and the eccentricity of the hyperbola H be the…

JEE Main 2024 — Mathematics Coordinate Geometry

2024mcqhard

Let the foci of a hyperbola HHH coincide with the foci of the ellipse E:(x−1)2100+(y−1)275=1E: \frac{(x-1)^2}{100}+\frac{(y-1)^2}{75}=1E:100(x−1)2​+75(y−1)2​=1 and the eccentricity of the hyperbola HHH be the reciprocal of the eccentricity of the ellipse EEE. If the length of the transverse axis of HHH is α\alphaα and the length of its conjugate axis is β\betaβ, then 3α2+2β23 \alpha^2+2 \beta^23α2+2β2 is equal to

Official previous-year question

Held on 9 Apr 2024 · Verified 6 Jul 2026.

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  1. A

    237

  2. B

    242

  3. C

    205

  4. D

    225

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