Given: A(α,0) and B(0,β) lies on the line 5x+7y=50.
⇒5(α)+7(0)=50,5(0)+7(β)=50
⇒α=10,β=750
Also, P divide the line segment AB internally in the ratio 7:3.
⇒P≡(7+37×0+3×10,7+37×750+3×0)
⇒P≡(3,5)
⇒ae=3 as perpendicular from S passes through P
Now, 3x−25=0 is a directrix of the ellipse E:a2x2+b2y2=1
⇒x=325
We know that, directrix of an ellipse is given by x=±ea
⇒ea=325

Also, ae=3
⇒a=5,b=4
Length of LR =a2b2=532