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Let a circle passing through (2,0) have its centre at the point (h, k). Let (x_c, y_c ) be the point of intersection of the lines 3 x+5 y=1 and (2+c)…

JEE Main 2024 — Mathematics Coordinate Geometry

2024mcqhard

Let a circle passing through (2,0)(2,0)(2,0) have its centre at the point (h,k)(h, k)(h,k). Let (xc,yc)\left(x_c, y_c\right)(xc​,yc​) be the point of intersection of the lines 3x+5y=13 x+5 y=13x+5y=1 and (2+c)x+5c2y=1(2+c) x+5 c^2 y=1(2+c)x+5c2y=1. If h=lim⁡c→1xc\displaystyle \mathrm{h}=\lim _{\mathrm{c} \rightarrow 1} x_{\mathrm{c}}h=c→1lim​xc​ and k=lim⁡c→1yc\displaystyle \mathrm{k}=\lim _{\mathrm{c} \rightarrow 1} y_{\mathrm{c}}k=c→1lim​yc​, then the equation of the circle is :

Official previous-year question

Held on 9 Apr 2024 · Verified 6 Jul 2026.

Options

  1. A

    25x2+25y2−2x+2y−60=025 x^2+25 y^2-2 x+2 y-60=025x2+25y2−2x+2y−60=0

  2. B

    5x2+5y2−4x+2y−12=05 x^2+5 y^2-4 x+2 y-12=05x2+5y2−4x+2y−12=0

  3. C

    5x2+5y2−4x−2y−12=05 x^2+5 y^2-4 x-2 y-12=05x2+5y2−4x−2y−12=0

  4. D

    25x2+25y2−20x+2y−60=025 x^2+25 y^2-20 x+2 y-60=025x2+25y2−20x+2y−60=0

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