Image of point (−4,5) ax−x1=by−y1=−2(a2+b2ax1+by1+c) Line: x+2y−2=0 1x+4=2y−5=−2(12+22−4+10−2) =5−8 x=−4−58=−528 y=−516+5=59 Point lies on circle (x+4)2+(y−3)2=r2 2564+(59−3)2=r225100=r2,r=2
If the image of the point (−4,5) in the line x+2y=2 lies on the circle (x+4)2+(y−3)2=r2, then r is equal to:
Held on 8 Apr 2024 · Verified 6 Jul 2026.
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