
$\begin{aligned}
& T=S_1 \
& x_1+y_1=x_1^2+y_1^2 \
& \alpha x_1=x_1^2+y_1^2 \
& \alpha\left(2 t^2\right)=4 t^4+16 t^2 \
& \alpha=2 t^2+8 \
& \frac{\alpha-8}{2}=t^2
\end{aligned}$
Also, 4t4+16t2−4<0 $\begin{aligned}
& \mathrm{t}^2=-2+\sqrt{5} \
& \alpha=4+2 \sqrt{5} \
& \therefore \alpha \in(8,4+2 \sqrt{5}) \
& \therefore(2 \mathrm{q}-\mathrm{p})^2=80
\end{aligned}$