Given,
P(a1,b1) and Q(a2,b2) be two distinct points on a circle with center C(2,3),
And O be the origin and OC be perpendicular to both CP and CQ,
So, PCQ will be a straight line
Now on plotting the diagram we get,

So, OC=(2)2+(3)2=5
Now let CP=CQ=I
Now by using area of triangle OCP=21×OC×I we get,
235=21×5×I⇒I=7
And OP=OQ=OC2+I2=12
So, a12+b12+a22+b22=OP2+OQ2=12+12=24