Consider ellipses E_k:kx^2+k^2 y^2=1,k=1,2,… ,20. Let C_k be the circle which touches the four chords joining the end points (one on minor axis and…
JEE Main 2023 — Mathematics Coordinate Geometry
2023mcqhard
Consider ellipses Ek:kx2+k2y2=1,k=1,2,…,20. Let Ck be the circle which touches the four chords joining the end points (one on minor axis and another on major axis) of the ellipse Ek. If rk is the radius of the circle Ck, then the value of k=1∑20rk21 is
Official previous-year question
Held on 11 Apr 2023 · Verified 6 Jul 2026.
Options
A
3080
B
2870
C
3210
D
3320
Did you get this right?
Sign in to track your attempts and accuracy.
Solution
Given,
Ek:kx2+k2y2=1
⇒Ek:(k1)2x2+(k1)2y2=1
Now equation of the chord joining the points (\frac{1}{\sqrt{k}},0)&(0,\frac{1}{k}) will be,
Lk:(k1)x+(k1)y=1
⇒kx+ky−1=0
Now rk= Perpendicular distance of Lk from (0,0) we get,
rk=∣k+k2−1∣
⇒rk2=k+k21
Now putting the value of rk2 in k=1∑20rk21 we get,
k=1∑20rk21=k=1∑20k+k2=220×21+620×21×41
=210+2870=3080
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.