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Let the eccentricity of an ellipse x^2 a^2+ y^2 b^2=1,a>b, be 1 4. If this ellipse passes through the point (-4√ 2 5,3), then a^2+b^2 is equal to

JEE Main 2022 — Mathematics Coordinate Geometry

2022mcqeasy

Let the eccentricity of an ellipse x2a2+y2b2=1,a>b\frac{{x}^{2}}{{a}^{2}}+\frac{{y}^{2}}{{b}^{2}}=1,a>ba2x2​+b2y2​=1,a>b, be 14\frac{1}{4}41​. If this ellipse passes through the point (−425,3)(-4\sqrt{\frac{2}{5}},3)(−452​​,3), then a2+b2{a}^{2}+{b}^{2}a2+b2 is equal to

Official previous-year question

Held on 27 Jun 2022 · Verified 6 Jul 2026.

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  1. A

    292929

  2. B

    313131

  3. C

    323232

  4. D

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