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Let the abscissae of the two points P and Q be the roots of 2x^2-rx+p=0 and the ordinates of P and Q be the roots of x^2-sx-q=0. If the equation of…

JEE Main 2022 — Mathematics Coordinate Geometry

2022integereasy

Let the abscissae of the two points PPP and QQQ be the roots of 2x2−rx+p=02{x}^{2}-rx+p=02x2−rx+p=0 and the ordinates of PPP and QQQ be the roots of x2−sx−q=0{x}^{2}-sx-q=0x2−sx−q=0. If the equation of the circle described on PQPQPQ as diameter is 2(x2+y2)−11x−14y−22=02({x}^{2}+{y}^{2})-11x-14y-22=02(x2+y2)−11x−14y−22=0, then 2r+s−2q+p2r+s-2q+p2r+s−2q+p is equal to ______.

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Held on 25 Jun 2022 · Verified 6 Jul 2026.

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