A=(a3,a)
B=(a−3,a) is the image of A on y-axis
C=(−a3,−a) is the image of B in x-axis
D(3cosθ,asinθ)
Area of triangle ACD will be
21∣a3−a33cosθa−aasinθ111∣
=3a(cosθ−sinθ)
The maximum area of triangle is 3a2
i.e. 3a2=12
⇒a=8
JEE Main 2022 — Mathematics Coordinate Geometry
Let A(a3,a),a>0, be a fixed point in the xy-plane. The image of A in y-axis be B and the image of B in x-axis be C. If D(3cosθ,asinθ), is a point in the fourth quadrant such that the maximum area of ΔACD is 12 square units, then a is equal to _____
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