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Let x=2t,y= t^2 3 be a conic. Let S be the focus and B be the point on the axis of the conic such that SAperp BA, where A is any point on the conic.…

JEE Main 2022 — Mathematics Coordinate Geometry

2022mcqmedium

Let x=2t,y=t23x=2t,y=\frac{{t}^{2}}{3}x=2t,y=3t2​ be a conic. Let SSS be the focus and BBB be the point on the axis of the conic such that SA⊥BASA\perp BASA⊥BA, where AAA is any point on the conic. If kkk is the ordinate of the centroid of the ΔSAB\Delta SABΔSAB, then limt→1k\underset{t\rightarrow 1}{\mathrm{lim}}kt→1lim​k is equal to

Official previous-year question

Held on 25 Jun 2022 · Verified 6 Jul 2026.

Options

  1. A

    1718\frac{17}{18}1817​

  2. B

    1918\frac{19}{18}1819​

  3. C

    1118\frac{11}{18}1811​

  4. D

    1318\frac{13}{18}1813​

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