Let C be a circle passing through the points A(2,-1) and B(3,4). The line segment AB is not a diameter of C. If r is the radius of C and its centre…
JEE Main 2022 — Mathematics Coordinate Geometry
2022mcqhard
Let C be a circle passing through the points A(2,−1) and B(3,4). The line segment AB is not a diameter of C. If r is the radius of C and its centre lies on the circle (x−5)2+(y−1)2=213, then r2 is equal to
Official previous-year question
Held on 26 Jun 2022 · Verified 6 Jul 2026.
Options
A
32
B
265
C
261
D
30
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Solution
Equation of line joining AB is
y+1=5(x−2)
i.e. 5x−y−11=0
Also AB=(3−2)2+(4+1)2=26
r is the radius of the circle C
For the circle (x−5)2+(y−1)2=213
centre is (5,1) and radius R=213
Equation of perpendicular bisector of AB will be y−1=−51(x−5)⇒x+5y−10=0
Solving this equation of line with (x−5)2+(y−1)2=213, we get
M as (25,23)
So M lies on the line joining AB.
Now r2=CM2+AM2
=(2×213)2+(213)2
r2=265
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