y=mx+c
3=m+c
2=∣1+32mm−32∣
⇒6m+2=±(m−32)
from Positive sign
⇒5m=−42⇒m=5−42
from negative sign
⇒6m+2=−m+32
⇒7m=22⇒m=722
According to options take m=5−42
So y=5−42x+53+42
42x+5y−(15+42)=0
The equation of one of the straight lines which passes through the point (1,3) and makes an angles tan−1(2) with the straight line, y+1=32x is
Held on 18 Mar 2021 · Verified 6 Jul 2026.
42x+5y−(15+42)=0
52x+4y−(15+42)=0
42x+5y−42=0
42x−5y−(5+42)=0
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