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Let the lengths of intercepts on x -axis and y -axis made by the circle x^2+y^2+ax+2ay+c=0, (a<0) be 2√2 and 2√5, respectively. Then the shortest…

JEE Main 2021 — Mathematics Coordinate Geometry

2021mcqmedium

Let the lengths of intercepts on xxx -axis and yyy -axis made by the circle x2+y2+ax+2ay+c=0,{x}^{2}+{y}^{2}+ax+2ay+c=0,x2+y2+ax+2ay+c=0, (a<0)(a<0)(a<0) be 222\sqrt{2}22​ and 252\sqrt{5}25​, respectively. Then the shortest distance from origin to a tangent to this circle which is perpendicular to the line x+2y=0,x+2y=0,x+2y=0, is equal to :

Official previous-year question

Held on 16 Mar 2021 · Verified 6 Jul 2026.

Options

  1. A

    11\sqrt{11}11​

  2. B

    7\sqrt{7}7​

  3. C

    6\sqrt{6}6​

  4. D

    10\sqrt{10}10​

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