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A hyperbola passes through the foci of the ellipse x^2 25+ y^2 16=1 and its transverse and conjugate axes coincide with major and minor axes of the…

JEE Main 2021 — Mathematics Coordinate Geometry

2021mcqmedium

A hyperbola passes through the foci of the ellipse x225+y216=1\frac{{x}^{2}}{25}+\frac{{y}^{2}}{16}=125x2​+16y2​=1 and its transverse and conjugate axes coincide with major and minor axes of the ellipse, respectively. If the product of their eccentricities is one, then the equation of the hyperbola is:

Official previous-year question

Held on 25 Feb 2021 · Verified 6 Jul 2026.

Options

  1. A

    x29−y216=1\frac{{x}^{2}}{9}-\frac{{y}^{2}}{16}=19x2​−16y2​=1

  2. B

    x2−y2=9{x}^{2}-{y}^{2}=9x2−y2=9

  3. C

    x29−y225=1\frac{{x}^{2}}{9}-\frac{{y}^{2}}{25}=19x2​−25y2​=1

  4. D

    x29−y24=1\frac{{x}^{2}}{9}-\frac{{y}^{2}}{4}=19x2​−4y2​=1

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