Equation of line is
3x+1y=1⇒x+3y−3=0
if image is(x1,y1)
Then,
1x1+1=3y1+4=−2(10−1−12−3)
x1+1=3y1+4=516
⇒x1=511,y1=528
Let L denote the line in the xy-plane with x and y intercepts as 3 and 1 respectively. Then the image of the point(−1,−4) in the line is :
Held on 6 Sept 2020 · Verified 6 Jul 2026.
(511,528)
(529,58)
(58,529)
(529,511)
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