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Let e_1 and e_2 be the eccentricities of the ellipse x^2 25+ y^2 b^2=1(b<5) and the hyperbola x^2 16- y^2 b^2=1 respectively satisfying e_1 e_2=1. If…

JEE Main 2020 — Mathematics Coordinate Geometry

2020mcqmedium

Let e1{e}_{1}e1​ and e2{e}_{2}e2​ be the eccentricities of the ellipse x225+y2b2=1(b<5)\frac{{x}^{2}}{25}+\frac{{y}^{2}}{{b}^{2}}=1(b<5)25x2​+b2y2​=1(b<5) and the hyperbola x216−y2b2=1\frac{{x}^{2}}{16}-\frac{{y}^{2}}{{b}^{2}}=116x2​−b2y2​=1 respectively satisfying e1e2=1{e}_{1}{e}_{2}=1e1​e2​=1. If α\alphaα and β\betaβ are the distances between the foci of the ellipse and the foci of the hyperbola respectively, then the ordered pair (α,β)(\alpha ,\beta )(α,β) is equal to:

Official previous-year question

Held on 3 Sept 2020 · Verified 6 Jul 2026.

Options

  1. A

    (8,10)(8,10)(8,10)

  2. B

    (203,12)(\frac{20}{3},12)(320​,12)

  3. C

    (8,12)(8,12)(8,12)

  4. D

    (245,10)(\frac{24}{5},10)(524​,10)

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