Mid point of PQ is (2k+1,27)
And slope of PQ=1−k1
So equation of perpendicular bisector of PQ
y−27=(k−1)(x−2k+1)
It's y intercept =−4. So, this equation must satisfy (0,−4).
⇒−215=−(2k2−1)
k2=16⇒k=±4
If the perpendicular bisector of the line segment joining the points P(1,4) and Q(k,3) has y-intercept equal to −4, then a value of k is;
Held on 4 Sept 2020 · Verified 6 Jul 2026.
−2
−4
14
15
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