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If the line, 2x-y+3=0 is at a distance 1 √5 and 2 √5 from the lines 4x-2y+α =0 and 6x-3y+β =0 respectively, then the sum of all possible values of α…

JEE Main 2020 — Mathematics Coordinate Geometry

2020integereasy

If the line, 2x−y+3=02x-y+3=02x−y+3=0 is at a distance 15\frac{1}{\sqrt{5}}5​1​ and 25\frac{2}{\sqrt{5}}5​2​ from the lines 4x−2y+α=04x-2y+\alpha =04x−2y+α=0 and 6x−3y+β=06x-3y+\beta =06x−3y+β=0 respectively, then the sum of all possible values of α\alphaα and β\betaβ is ____________.

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Held on 5 Sept 2020 · Verified 6 Jul 2026.

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