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If a line y=mx+c, is a tangent to the circle (x-3)^2+y^2=1, and it is perpendicular to a line L_1, where L_1 is the tangent to the circle x^2+y^2=1,…

JEE Main 2020 — Mathematics Coordinate Geometry

2020mcqmedium

If a line y=mx+cy=mx+cy=mx+c, is a tangent to the circle (x−3)2+y2=1{(x-3)}^{2}+{y}^{2}=1(x−3)2+y2=1, and it is perpendicular to a line L1,{L}_{1},L1​, where L1{L}_{1}L1​ is the tangent to the circle x2+y2=1{x}^{2}+{y}^{2}=1x2+y2=1, at the point (12,12)(\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}})(2​1​,2​1​), then

Official previous-year question

Held on 8 Jan 2020 · Verified 6 Jul 2026.

Options

  1. A

    c2−7c+6=0{c}^{2}-7c+6=0c2−7c+6=0

  2. B

    c2+7c+6=0{c}^{2}+7c+6=0c2+7c+6=0

  3. C

    c2+6c+7=0{c}^{2}+6c+7=0c2+6c+7=0

  4. D

    c2−6c+7=0{c}^{2}-6c+7=0c2−6c+7=0

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