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For some θ ∈ (0, π 2), if the eccentricity of the hyperbola, x^2-y^2 sec^2θ =10 is √5 times the eccentricity of the ellipse, x^2 sec^2θ +y^2=5, then…

JEE Main 2020 — Mathematics Coordinate Geometry

2020mcqmedium

For some θ∈(0,π2),\theta \in (0,\frac{\pi }{2}),θ∈(0,2π​), if the eccentricity of the hyperbola, x2−y2sec2θ=10{x}^{2}-{y}^{2}{\mathrm{sec}}^{2}\theta =10x2−y2sec2θ=10 is 5\sqrt{5}5​ times the eccentricity of the ellipse, x2sec2θ+y2=5,{x}^{2}{\mathrm{sec}}^{2}\theta +{y}^{2}=5,x2sec2θ+y2=5, then the length of the latus rectum of the ellipse, is

Official previous-year question

Held on 2 Sept 2020 · Verified 6 Jul 2026.

Options

  1. A

    262\sqrt{6}26​

  2. B

    30\sqrt{30}30​

  3. C

    253\frac{2\sqrt{5}}{3}325​​

  4. D

    453\frac{4\sqrt{5}}{3}345​​

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