Let the coordinates of C be (t2,2t).
Area of ΔABC=21∣t2942t6−4111∣

Δ=5∣(6+t−t2)∣, t∈(−2,3)
dtdΔ=1−2t=0⇒t=21
dt2d2△=−2, hence area is maximum at t=21
∴Δmax=4125=3141
JEE Main 2019 — Mathematics Coordinate Geometry
Let A(4,−4) and B(9,6) be points on the parabola, y2=4x. Let C be chosen on the arc AOB of the parabola, where O is the origin, such that the area of ΔACB is maximum. Then, the area (in sq. units) of ΔACB , is:
Held on 9 Jan 2019 · Verified 6 Jul 2026.
32
3143
3021
3141
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