
Let centre be C(h,k) CQ=CP=r ⇒CQ2=CP2 (h−0)2+(k±0)2=CM2+MP2 h2+(k±2 b)2=k2+4a2 h2+k2+4b2±4bk=k2+4a2 Then, the locus of centre C(h,k) x2+4b2±4by=4a2 Hence, the above locus of the centre of circle is a parabola.
JEE Main 2019 — Mathematics Coordinate Geometry
A circle cuts a chord of length 4 a on the x -axis and passes through a point on the y -axis, distant 2 b from the origin. Then the locus of the centre of this circle, is:
Held on 11 Jan 2019 · Verified 6 Jul 2026.
a hyperbola
an ellipse
a straight line
a parabola
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