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The locus of the point of intersection of the lines √2x-y+4√2k=0 and √2kx+ky-4√2=0 (k is any non-zero real parameter) is

JEE Main 2018 — Mathematics Coordinate Geometry

2018mcqmedium

The locus of the point of intersection of the lines 2x−y+42k=0\sqrt{2}x-y+4\sqrt{2}k=02​x−y+42​k=0 and 2kx+ky−42=0\sqrt{2}kx+ky-4\sqrt{2}=02​kx+ky−42​=0 (kkk is any non-zero real parameter) is

Official previous-year question

Held on 16 Apr 2018 · Verified 6 Jul 2026.

Options

  1. A

    an ellipse whose eccentricity is 13\frac{1}{\sqrt{3}}3​1​

  2. B

    a hyperbola whose eccentricity is 3\sqrt{3}3​

  3. C

    a hyperbola with length of its transverse axis 828\sqrt{2}82​

  4. D

    an ellipse with length of its major axis 828\sqrt{2}82​

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