The equation of a tangent to the given circle at (2,2) is
x(2)+y(2)+(x+2)−2(y+2)−4=0⇒3x−6=0⇒x=2
Family of the circle touching a given line at a given point
(x−2)2+(y−2)2+λ(x−2)=0.
⇒x2+y2+(λ−4)x−4y+(8−2λ)=0
Radius=3=(2λ−4)2+4−(8−2λ)
⇒9=4λ2−8λ+16−4+2λ
⇒36=λ2−8λ+16−16+8λ
⇒λ=±6
Hence, equation of the circle is x2+y2−10x−4y+20=0.
So, x-intercept=225−20=25.