Given eccentricity of the ellipse e=53.
Distance between foci is 2ae=6
⇒a=5.
Also, b2=a2(1−e2)
⇒ b2=25(1−259)
⇒ b=4
Area =4(21ab)=2ab=40
Consider an ellipse, whose center is at the origin and its major axis is along the x-axis. If its eccentricity is 53 and the distance between its foci is 6, then the area (in sq. units) of the quadrilateral inscribed in the ellipse, with the vertices as the vertices of the ellipse, is:
Held on 8 Apr 2017 · Verified 6 Jul 2026.
32
80
40
8
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