Equation of line QR perpendicular to L:x−y=4 is
x+y−c=0…(1)
Distance of QR from (2,1) is 23
⇒23=2∣2+1−c∣
⇒26=∣3−c∣
⇒c−3=±26⇒c=3±26
Line can be x+y=3±26
x+y=3−26 (since Q is in the third quadrant)
The point (2,1) is translated parallel to the line L:x−y=4 by 23 units. If the new point Q lies in the third quadrant, then the equation of the line passing through Q and perpendicular to L is
Held on 9 Apr 2016 · Verified 6 Jul 2026.
x+y=2−6
2x+2y=1−6
x+y=3−36
x+y=3−26
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