The centre of the given circle x2+y2−4x+6y−12=0 is (2,−3) and the radius is 5.
The distance between the centres 52 and radius is 5. The triangle OPQ is a right angled triangle
OQ=(52)2+52=(53)2=53
Hence answer is 53
If one of the diameters of the circle, given by the equation, x2+y2−4x+6y−12=0, is a chord of a circle S, whose centre is at (−3,2), then the radius of S is
Held on 3 Apr 2016 · Verified 6 Jul 2026.
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