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If one of the diameters of the circle, given by the equation, x^2+y^2-4x+6y-12=0, is a chord of a circle S, whose centre is at (-3,2), then the…

JEE Main 2016 — Mathematics Coordinate Geometry

2016mcqmedium

If one of the diameters of the circle, given by the equation, x2+y2−4x+6y−12=0,{x}^{2}+{y}^{2}-4x+6y-12=0,x2+y2−4x+6y−12=0, is a chord of a circle SSS, whose centre is at (−3,2)(-3,2)(−3,2), then the radius of SSS is

Official previous-year question

Held on 3 Apr 2016 · Verified 6 Jul 2026.

Options

  1. A

    555

  2. B

    101010

  3. C

    525\sqrt{2}52​

  4. D

    535\sqrt{3}53​

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