
Point of intersection of lines
x−y=1 and 2x+y=3
O is (34,31)
Slope of OP=34−131+1=3134=4
Slope of tangent =−41
⇒ Equation of tangent :y+1=−41(x−1)
⇒4y+4=−x+1
⇒x+4y+3=0
JEE Main 2016 — Mathematics Coordinate Geometry
Equation of the tangent to the circle, at the point (1,−1), whose center, is the point of intersection of the straight lines x−y=1 and 2x+y=3 is:
Held on 10 Apr 2016 · Verified 6 Jul 2026.
x+4y+3=0
3x−y−4=0
x−3y−4=0
4x+y−3=0
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