Let image is (α,β)
∴ point (22+α,23+β) lies on the given variable line.
∴ 2(22+α)−3(23+β)+4+k(22+α−2×23+β+3)=0
⇒2α−3β+3+k(α−2β+2)=0.......(1)
again, product of two slopes =−1
⇒2−α3−β×3+2k2+k=−1
⇒6−2β+k(3−β)=−(6−3α)−k(4−2α)
⇒k(7−2α−β)=3α+2β−12
⇒k=7−2α−β3α+2β−12
Substituting value of k in ,(1) we get
2α−3β+3+7−2α−β3α+2β+−12(α−2β+2)=0
⇒14α−4α2−2αβ−21β+6αβ+3β2+21−6α−3β+3α2−6αβ+6α+2αβ−4β2+4β−12α+24β−24=0
⇒α2+β2−2a−4β+3=0
∴ Locus is x2+y2−2x−4y+3=0
Which is a circle with radius =1+4−3=2