A straight line L through the point (3, -2) is inclined at an angle of 60° to the line √3x+y=1. If L also intersects the X-axis, then the equation of…
JEE Main 2015 — Mathematics Coordinate Geometry
2015mcqmedium
A straight line L through the point (3,−2) is inclined at an angle of 60∘ to the line 3x+y=1. If L also intersects the X-axis, then the equation of L is:
Official previous-year question
Held on 11 Apr 2015 · Verified 6 Jul 2026.
Options
A
y+3x+2−33=0
B
3y−x+3+23=0
C
3y+x−3+23=0
D
y−3x+2+33=0
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Solution
Let m be the slope of the line,
then tan60o=∣1−m3m+3∣
⇒3=∣1−3mm+3∣
⇒±3=1−3mm+3
∴3−3m=m+3 or −3+3m=m+3
4m=0 or 2m=23
m=0 or m=3
Since L intersects X-axis we take m=3
and get y=3x+c
Since it passes through (3,−2), therefore line will become y−3x+2+33=0
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