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Let L_1 be the length of the common chord of the curves x^2+y^2=9 and y^2=8 x, and L_2 be the length of the latus rectum of y^2=8 x, then:

JEE Main 2014 — Mathematics Coordinate Geometry

2014mcqmedium

Let L1\mathrm{L}_1L1​ be the length of the common chord of the curves x2+y2=9x^2+y^2=9x2+y2=9 and y2=8xy^2=8 xy2=8x, and L2L_2L2​ be the length of the latus rectum of y2=8xy^2=8 xy2=8x, then:

Official previous-year question

Held on 11 Apr 2014 · Verified 6 Jul 2026.

Options

  1. A

    L1>L2\mathrm{L}_1>\mathrm{L}_2L1​>L2​

  2. B

    L1=L2\mathrm{L}_1=\mathrm{L}_2L1​=L2​

  3. C

    L1<L2\mathrm{L}_1 < \mathrm{L}_2L1​<L2​

  4. D

    L1 L2=2\frac{\mathrm{L}_1}{\mathrm{~L}_2}=\sqrt{2} L2​L1​​=2​

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