We have x2+(8x)=9x2+9x−x−9=0x(x+9)−1(x+9)=0(x+9)(x−1)=0x=−9,1 for x=1,y=±22x=±22 L1= Length of AB=(22+22)2+(1−1)2=42 L2= Length of latus rectum =4a=4×2=8 L1<L2
Let L1 be the length of the common chord of the curves x2+y2=9 and y2=8x, and L2 be the length of the latus rectum of y2=8x, then:
Held on 11 Apr 2014 · Verified 6 Jul 2026.
L1>L2
L1=L2
L1<L2
L2L1=2
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