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Let a and b be any two numbers satisfying 1 a^2+ 1 b^2= 1 4. Then, the foot of perpendicular from the origin on the variable line x a+ y b=1 lies on :

JEE Main 2014 — Mathematics Coordinate Geometry

2014mcqhard

Let aaa and bbb be any two numbers satisfying 1a2+1b2=14.\frac{1}{{a}^{2}}+\frac{1}{{b}^{2}}=\frac{1}{4}.a21​+b21​=41​. Then, the foot of perpendicular from the origin on the variable line xa+yb=1\frac{x}{a}+\frac{y}{b}=1ax​+by​=1 lies on :

Official previous-year question

Held on 9 Apr 2014 · Verified 6 Jul 2026.

Options

  1. A

    A circle of radius =2=2=2

  2. B

    A hyperbola with each semi-axis =2= \sqrt{ 2 }=2​.

  3. C

    A hyperbola with each semi-axis =2=2=2

  4. D

    A circle of radius =2= \sqrt{ 2 }=2​

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