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Statement-1: The line x-2 y=2 meets the parabola, y^2+2 x=0 only at the point (-2,-2). Statement-2: The line y=m x- 1 2 m(m ≠ 0) is tangent to the…

JEE Main 2013 — Mathematics Coordinate Geometry

2013mcqhard

Statement-1: The line x−2y=2x-2 y=2x−2y=2 meets the parabola, y2+2x=0y^2+2 x=0y2+2x=0 only at the point (−2,−2)(-2,-2)(−2,−2). Statement-2: The line y=mx−12m(m≠0)y=m x-\frac{1}{2 m}(m \neq 0)y=mx−2m1​(m=0) is tangent to the parabola, y2=−2xy^2=-2 xy2=−2x at the point (−12m2,−1m)\left(-\frac{1}{2 m^2},-\frac{1}{m}\right)(−2m21​,−m1​)

Official previous-year question

Held on 22 Apr 2013 · Verified 6 Jul 2026.

Options

  1. A

    Statement-1 is true; Statement- 2 is false.

  2. B

    Statement-1 is true; Statement-2 is true; Statement-2 is a correct explanation for statement-1.

  3. C

    Statement-1 is false; Statement-2 is true.

  4. D

    Statement-1 a true; Statement-2 is true; Statement-2 is not a correct explanation for statement-1.

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