Skip to main content

If two lines L_1 and L_2 in space, are defined by … z=(1-√μ) y+√μ then L_1 is perpendicular to L_2, for all nonnegative reals λ and μ, such that :

JEE Main 2013 — Mathematics Coordinate Geometry

2013mcqhard

If two lines L1L_1L1​ and L2L_2L2​ in space, are defined by L1={x=λy+(λ−1),z=(λ−1)y+λ} and L2={x=μy+(1−μ),\begin{aligned} & L_1=\{x=\sqrt{\lambda} y+(\sqrt{\lambda}-1), \\ & \quad z=(\sqrt{\lambda}-1) y+\sqrt{\lambda}\} \text { and } \\ & L_2=\{x=\sqrt{\mu} y+(1-\sqrt{\mu}), \end{aligned}​L1​={x=λ​y+(λ​−1),z=(λ​−1)y+λ​} and L2​={x=μ​y+(1−μ​),​ z=(1−μ)y+μ}z=(1-\sqrt{\mu}) y+\sqrt{\mu}\}z=(1−μ​)y+μ​} then L1L_1L1​ is perpendicular to L2L_2L2​, for all nonnegative reals λ\lambdaλ and μ\muμ, such that :

Official previous-year question

Held on 23 Apr 2013 · Verified 6 Jul 2026.

Options

  1. A

    λ+μ=1\sqrt{\lambda}+\sqrt{\mu}=1λ​+μ​=1

  2. B

    λ≠μ\lambda \neq \muλ=μ

  3. C

    λ+μ=0\lambda+\mu=0λ+μ=0

  4. D

    λ=μ\lambda=\muλ=μ

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics