x2=8y 3x2+y2=1 From (i) and (ii), 38y+y2=1⇒y=−3,31 When y=−3, then x2=−24, which is not possible. When y=31, then x=±326 Point of intersection are (326,31) and (−326,31) Required equation of the line, y−31=0⇒3y−1=0
Equation of the line passing through the points of intersection of the parabola x2=8y and the ellipse 3x2+y2=1 is :
Held on 9 Apr 2013 · Verified 6 Jul 2026.
y−3=0
y+3=0
3y+1=0
3y−1=0
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