Given lines are ax+2by+3b=0 and bx−2ay−3a=0 Since, required line is ∥ to x-axis ∴x=0 We put x=0 in given equation, we get 2by=−3b⇒y=−23 This shows that the required line is below x-axis at a distance of 23 from it.
The line parallel to x-axis and passing through the point of intersection of lines ax+2by+3b=0 and bx−2ay−3a=0, where (a,b)=(0,0) is
Held on 26 May 2012 · Verified 6 Jul 2026.
above x-axis at a distance 2/3 from it
above x-axis at a distance 3/2 from it
below x-axis at a distance 3/2 from it
below x-axis at a distance 2/3 from it
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