Given equation of ellipse is 16x2+b2y2=1 eccentricity =e=1−16b2 foci: ±ae=±41−16b2 Equation of hyperbola is 144x2−81y2=251 ⇒25144x2−2581y2=1 eccentricity =e=1+2581×14425=1+14481=144225=1215 foci: ±ae=±512×1215=±3 Since, foci of ellipse and hyperbola coincide & \therefore \pm 4 \sqrt{1-\frac{b^2}{16}}=\pm 3 \Rightarrow b^2=7 \ $$
If the foci of the ellipse x^2 16+ y^2 b^2=1 coincide with the foci of the hyperbola x^2 144- y^2 81= 1 25, then b^2 is equal to
JEE Main 2012 — Mathematics Coordinate Geometry
If the foci of the ellipse 16x2+b2y2=1 coincide with the foci of the hyperbola 144x2−81y2=251, then b2 is equal to
Held on 19 May 2012 · Verified 6 Jul 2026.
Options
- A
8
- B
10
- C
7
- D
9
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Coordinate Geometry in other years
More JEE Main Coordinate Geometry questions
Let $A,B$ be points on the two half-lines $x-\sqrt{3}|y|=\alpha$, $\alpha>0$ at a distance of $\alpha$ from their point of intersection $P$. The line segment $AB$ meets the angle bisector of the given half-lines at the point $Q$. If $PQ=\dfrac{9}{2}$ and $R$ is the radius of the circumcircle of $\triangle PAB$, then $\dfrac{\alpha^2}{R}$ is equal to ______
If a straight line drawn through the point of intersection of the lines $4x+3y-1=0$ and $3x+4y-1=0$, meets the co-ordinate axes at the points P and Q, then the locus of the mid point of PQ is:
Let $C$ be a circle having centre in the first quadrant and touching the $x$-axis at a distance of $3$ units from the origin. If the circle $C$ has an intercept of length $6\sqrt{3}$ on $y$-axis, then the length of the chord of the circle $C$ on the line $x - y = 3$ is :
Let O be the origin, and P and Q be two points on the rectangular hyperbola $xy = 12$ such that the mid point of the line segment PQ is $\left(\dfrac{1}{2}, -\dfrac{1}{2}\right)$. Then the area of the triangle OPQ equals:
Let the vertex $A$ of a triangle $ABC$ be $(1, 2)$, and the mid-point of the side $AB$ be $(5, -1)$. If the centroid of this triangle is $(3, 4)$ and its circumcenter is $(\alpha, \beta)$, then $21(\alpha + \beta)$ is equal to:
Other Mathematics topics for JEE Main
Keep practicing Coordinate Geometry
Work through every JEE Main Coordinate Geometry PYQ, year by year.