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The locus of the vertices of the family of parabolas y= a^3 x^2 3+ a^2 x 2-2 a is

JEE Main 2006 — Mathematics Coordinate Geometry

2006mcqhard

The locus of the vertices of the family of parabolas y=a3x23+a2x2−2ay=\frac{a^3 x^2}{3}+\frac{a^2 x}{2}-2 ay=3a3x2​+2a2x​−2a is

Official previous-year question

Held on 30 Apr 2006 · Verified 6 Jul 2026.

Options

  1. A

    xy=10564x y=\frac{105}{64}xy=64105​

  2. B

    xy=34x y=\frac{3}{4}xy=43​

  3. C

    xy=3516x y=\frac{35}{16}xy=1635​

  4. D

    xy=64105x y=\frac{64}{105}xy=10564​

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