Skip to main content

If the lines 3 x-4 y-7=0 and 2 x-3 y-5=0 are two diameters of a circle of area 49 π square units, the equation of the circle is

JEE Main 2006 — Mathematics Coordinate Geometry

2006mcqmedium

If the lines 3x−4y−7=03 x-4 y-7=03x−4y−7=0 and 2x−3y−5=02 x-3 y-5=02x−3y−5=0 are two diameters of a circle of area 49π49 \pi49π square units, the equation of the circle is

Official previous-year question

Held on 30 Apr 2006 · Verified 6 Jul 2026.

Options

  1. A

    x2+y2+2x−2y−47=0x^2+y^2+2 x-2 y-47=0x2+y2+2x−2y−47=0

  2. B

    x2+y2+2x−2y−62=0x^2+y^2+2 x-2 y-62=0x2+y2+2x−2y−62=0

  3. C

    x2+y2−2x+2y−62=0x^2+y^2-2 x+2 y-62=0x2+y2−2x+2y−62=0

  4. D

    x2+y2−2x+2y−47=0x^2+y^2-2 x+2 y-47=0x2+y2−2x+2y−47=0

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics